Question -
What will be the output of the following PHP code?$author = "nachiketh@example.com";$author = str_replace("a","@",$author);echo "Contact the author of this article at $author.";
Options:
A .  Error
B .  Contact the author of this article at n@chiketh@ex@mple.com
C .  Contact the author of this article at nachiketh@ex@mple.com
D .  Cont@ct the @uthor of this @rticle @t n@chiketh@ex@mple.com
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