If the tth term of an AP is s and sth term of the same AP is t, then an is ___.
Options:
A .  
t+s+n
B .  
t+s−n
C .  
t−s+n
D .  
t−s−n
Answer: Option B : B Given, at=a+(t−1)d=s,...(i) as=a+(s−1)d=t...(ii) ⇒(t−s)=a+(s−1)d−a−(t−1)d ⇒t−s=(s−t)d[from eqns. (i) and (ii)] ⇒(t−s)=−(t−s)d ⇒d=−1 From (i), we get a+(t−1)(−1)=s. ⇒a=s+t−1 an=a+(n−1)d ⇒an=s+t−1+(n−1)×(−1)=s+t−1−n+1=s+t−n
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