Discussion Forum : Limits Continuity And Differentiability
Question -


If limx→0kx cosec x = limx→0x cosec kx , then k =

Options:
A .   1
B .   -1
C .  
D .  
Answer: Option C
:
C

limx→0kx cosec x = limx→0 x cosec kx


= k limx→0xsinx =1klimx→0kxsinkx =k=1k=k=± 1



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