Discussion Forum : Limits Continuity And Differentiability
Question -


limx0(cosx)1/x4 

Options:
A .   0
B .   1 
C .   e 
D .   limit does not exist
Answer: Option A
:
A
limx0(cosx)1/x4=elimx0cosx1x4
elimx02sinx2x2.sinx2x2×14x2=e=0 

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