In an equilateral triangle sum of the distances of orthocenter from all the vertices is equal to - (Where 'R' is the circumradius of triangle)
Options:
A .  
R
B .  
2R
C .  
3R
D .  
4R
Answer: Option C : C Let the triangle be ABC and the orthocenter be O. We know that OA = 2RcosA It is given that triangle is equilateral. So cosA = cos (60°) = 12 And OA = R Similarly, OB = OC = R And the sum of them = OA + OB + OC = 3R
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