Discussion Forum : Limits Continuity And Differentiability
Question -
The value of limx→1[sin sin−1x] is
Answer: Option A
:
A
Since x→1 means x→1-, ∵ sin-1 x is not defined for x>1
limx→1[sin sin−1x]=limx→1−[sin sin−1x]=1
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:
A
Since x→1 means x→1-, ∵ sin-1 x is not defined for x>1
limx→1[sin sin−1x]=limx→1−[sin sin−1x]=1
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