One of the two events must occur. If the chance of one is 23 of the other, then odds in favour of the other are
Options:
A .  
2:3
B .  
1:3
C .  
3:1
D .  
3:2
Answer: Option D : D Let p be the probability of the other event, then the probability of the first event is 23 p. Since two events are totally exclusive, we have p+(23)p=1⇒p=35 Hence odds in favour of the other are 3 : 5 – 3, i.e, 3 : 2.
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