There are 4 torn books in a lot consisting of 10 books. If 5 books are selecet

Discussion Forum : Probability I

Question -

There are 4 torn books in a lot consisting of 10 books. If 5 books are seleceted at random what is the probability of presence of 2 torn books among the selected?

Options:

A .

\frac{1}{3}

B .

\frac{4}{21}

C .

\frac{10}{21}

D .

\frac{2}{7}

Answer: Option C
:
C

Total Sample space: $^{10} C_{5} = 252$

Favorable cases: $^{4} C_{2} \times^{6} C_{3} = 120$

Hence P(E)= $\frac{120}{252} = \frac{10}{21}$

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