The value of t a n 2 ( s e c − 1 3 ) + c o t 2 ( c o s e c − 1 4 ) is Options: A . &nbsp 20 B . &nbsp 21 C . &nbsp 23 D . &nbsp 25

Answer: Option C : C Let S e c − 1 3 = α , c o s e c − 1 4 = β ⇒ t a n 2 α + c o t 2 β = 9 − 1 + 16 − 1 = 23

The value of tan2(sec−13)+cot2(cosec−14) is

Question -

The value of $t a n^{2} (s e c^{- 1} 3) + c o t^{2} (c o s e c^{- 1} 4)$ is

Options:

A . 20

B . 21

C . 23

D . 25

Answer: Option C
:
C
Let

S e c^{- 1} 3 = α, c o s e c^{- 1} 4 = β \Rightarrow t a n^{2} α + c o t^{2} β = 9 - 1 + 16 - 1 = 23

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