If n ∈ N, then 11 n + 2 + 12 2 n + 1 is divisible by Options: A . &nbsp 113 B . &nbsp 123 C . &nbsp 133 D . &nbsp None of these

Answer: Option C : C Putting n = 1 in 11 n + 2 + 12 2 n + 1 We get, 11 1 + 2 + 12 2 × 1 + 1 = 11 3 + 12 3 = 3059, which is divisible by 133.

If n ∈ N, then 11n+2 + 122n+1 is divisible by

Question -

If n ∈ N, then $11^{n + 2}$ + $12^{2 n + 1}$ is divisible by

Options:

A . 113

B . 123

C . 133

D . None of these

Answer: Option C
:
C

Putting n = 1 in $11^{n + 2} + 12^{2 n + 1}$

We get, $11^{1 + 2} + 12 2 \times 1 + 1$ = $11^{3} + 12^{3}$ = 3059, which

is divisible by 133.

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