If n ∈ N, then x 2 n − 1 + y 2 n − 1 is divisible by Options: A . &nbsp x + y B . &nbsp x - y C . &nbsp x 2 + y 2 D . &nbsp x 2 +xy

If n ∈ N, then x2n−1+y2n−1 is divisible by

Question -

If n ∈ N, then $x^{2 n - 1} + y^{2 n - 1}$ is divisible by

Options:

A . x + y

B . x - y

C .

x^{2}

y^{2}

D .

x^{2}

+xy

Answer: Option A
:
A

$x^{2 n - 1} + y^{2 n - 1}$ is always contain equal odd power.

So it is always divisible by x + y.

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