Let P(n) denote the statement that n2 + n is odd. It is seem that P(n)

Question -

Let P(n) denote the statement that $n^{2}$ + n is odd. It

is seem that P(n) ⇒ P(n + 1), $P_{n}$ is true for all

Options:

A . n > 1

B . n

C . n > 2

D . None of these

Answer: Option D
:
D

P(n) = $n^{2}$ + n. It is always odd (statement) but

square of any odd number is always odd and

also, sum of odd number is always even. So

for no any 'n' for which this statement is true.

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