sin − 1 ( sin 10 ) = Options: A . &nbsp 10 B . &nbsp 3 π − 10 C . &nbsp π + 6 D . &nbsp 2 π − 6

Answer: Option B : B 3 π < 10 < 3 π + π 2 ∴ 10 rad ∈ Q 3 ∴ − π 2 < 3 π − 10 < 0 ∴ 3 π − 10 ∈ Q 4 Also sin ( 3 π − 10 ) = sin 10 Hence sin − 1 ( sin 10 ) = sin − 1 sin ( 3 π − 10 ) = 3 π − 10

sin−1(sin10)=

Discussion Forum : Inverse Trigonometric Functions

Question -

${sin}^{- 1} (sin 10) =$

Options:

A . 10

B .

3 π - 10

C .

π + 6

D .

2 π - 6

Answer: Option B
:
B

3 π < 10 < 3 π + \frac{π}{2} ∴ 10 rad \in Q_{3} ∴ - \frac{π}{2} < 3 π - 10 < 0 ∴ 3 π - 10 \in Q_{4} Also sin (3 π - 10) = sin 10 Hence {sin}^{- 1} (sin 10) = {sin}^{- 1} sin (3 π - 10) = 3 π - 10

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Discussion Forum : Inverse Trigonometric Functions

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