1 mole of N2 O4 (g) at 300K is kept in a closed container under 1 at

Discussion Forum : Chemical Equilibrium

Question -

1 mole of $N_{2} O_{4} (g)$ at 300K is kept in a closed container under 1 atm pressure. It is heated to 600K when 20 $%$ by mass of $N_{2} O_{4} (g)$ decomposes to $N O_{2} (g)$ . The resultant pressure is

Options:

A . 1.2 atm

B . 2.4 atm

C . 2.0 atm

D . 1.0 atm

Answer: Option B
:
B
Correct option is b).

\begin{matrix} N_{2} O_{4} ⇋ & 2 N O_{2} I n i t i a l m o l e s & 1 & 0 \end{matrix}

Total moles=0.8+0.4=1.2
Applying,

P V = n R T

, at constant volume,

\frac{P 1}{n 1 T 1} = \frac{P}{n 2 T 2}

\frac{1}{1 X 300} = \frac{P_{2}}{1.2 X 600}

P_{2} = 2.4 a t m .

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Discussion Forum : Chemical Equilibrium

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