At 30∘C,Kp for the dissociation reaction: SO2Cl2(g)⇋SO2(g)+Cl2(g)is2.9x10−2~atm. If the total pressure is 1 atm, the degree of dissociation of SO2Cl2is(assume1−α2=1)
Options:
A .  
85%
B .  
12%
C .  
17%
D .  
35%
Answer: Option C : C Correct option is c). SO2Cl2(g)⇋SO2(g)+Cl2(g)1001−ααα Total moles = 1+α Pso2Cl2=1−α/1+α,Pso2=α/1+α,Pcl2=α/1+α Kp=(α/1+α)2/(1−α/1+α)=α2/1−α2≈α2 α=√Kp=(2.9×10−2=0.17,i.e.,17%
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