In the reaction C 2 O 2 − 4 + M n O − 4 + H + ⟶ M n 2 + + C O 2 + H 2 O the reductant is Options: A . &nbsp C 2 O 2 − 4 B . &nbsp M n O − 4 C . &nbsp M n 2 + D . &nbsp H +

Answer: Option A : A C 2 O 2 − 4 + M n O − 4 + H + ⟶ M n 2 + + C O 2 + H 2 O In this reaction C 2 O 2 − 4 act as a reducing agent.

In the reaction C2O2−4+MnO−4+H+⟶Mn2++CO2+H2O the re

Question -

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} ⟶ M n^{2 +} + C O_{2} + H_{2} O$ the reductant is

Options:

A .

C_{2} O_{4}^{2 -}

B .

M n O_{4}^{-}

C .

M n^{2 +}

D .

H^{+}

Answer: Option A
:
A

$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} ⟶ M n^{2 +} + C O_{2} + H_{2} O$
In this reaction $C_{2} O_{4}^{2 -}$ act as a reducing agent.

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