The number of electrons involved in the reduction of Cr2O2−7 in acidic solutio

Question -

The number of electrons involved in the reduction of $C r_{2} O_{7}^{2 -}$ in acidic solution to $C r^{3 +}$ is

Options:

A . 0

B . 2

C . 3

D . 5

Answer: Option C
:
C

In this reaction three electrons are required for the reduction of $C r_{2} O_{7}^{2 -}$ into $C r^{3 +}$

Was this answer helpful ?

Next Question