Discussion Forum : Sound
Question -


In the figure shown, a source of sound of frequency 510 Hz moves with constant velocity = 20 m/s in the direction shown. The wind is blowing at a constant velocity = 20 m/s towards an observer who is at rest at point B. Corresponding to the sound emitted by the source at initial position A, the frequency detected by the observer is equal to (speed of sound relative to air is 330 m/s)

Options:
A .   510 Hz
B .   500 Hz
C .   525 Hz
D .   550 Hz
Answer: Option C
:
C
Apparent frequency is given by ​n=n(u+vw)(u+vwvscos60) =510(330+20)330+2020cos60 =510×350340=525Hz

Was this answer helpful ?
Next Question
Submit Your Solution hear:

Your email address will not be published. Required fields are marked *