A man standing on a platform hears the sound of frequency 605 Hz coming from 550 Hz train whistle moving towards the platform. If the velocity of sound is 330 m/s. What is the speed of train?
Options:
A .  
30 m/s
B .  
35 m/s
C .  
40 m/s
D .  
45 m/s
Answer: Option A : A Apparent Frequency is given by: n′=n(v+v0v−vs) 605=550(330+0330−vs) vs=30m/s
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