Speed of sound wave is v. If a reflector moves towards a stationary source emitting waves of frequency f with speed u, the wavelength of reflected waves will be
Options:
A .  
v−uv+uf
B .  
v+uvf
C .  
v+uv−uf
D .  
v−uvf
Answer: Option C : C Apparent frequency for reflector (which will act here as an observer) would be f1=(v+uv)f Where f is the actual frequency of source. The reflector will now behave as a source. The apparent frequency will now become f2=(vv−u)f1 Substituting the value of f1 we get f2=(v+uv−u)f
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