A body initially at 80∘ C cools to 64∘ C in 5 minutes and to 52∘ C in 10 minutes. The temperature of the body after 15 minutes will be
Options:
A .  
42.7∘ C
B .  
35∘ C
C .  
47∘ C
D .  
40∘ C
Answer: Option A : A According to Newton law of cooling θ1−θ2t=K[θ1−θ22−θ0] For first process : (80−64)5=K[80+642−θ0] ....(i) For second process : (80−52)10=K[80+522−θ0] ....(ii) For third process : (80−θ)15=K[80+θ2−θ0] ....(iii) On solving equation (i) and (ii) we get K=115 and θ0=24∘C . Putting these values in equation (iii) we get θ=42.7∘C
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