The current I in the circuit shown in figure is Options: A . &nbsp 1 45 A B . &nbsp 1 15 A C . &nbsp 1 10 A D . &nbsp 1 5 A

Answer: Option C : C The equivalent resistance is given by 1 R = 1 60 + 1 30 = 3 60 R = 20 ohm. Therefore I = 2 20 = 1 10 A

The current I in the circuit shown in figure is

Discussion Forum : Current Electricity

Question -

The current I in the circuit shown in figure is

Options:

A .

\frac{1}{45}

B .

\frac{1}{15}

C .

\frac{1}{10}

D .

\frac{1}{5}

Answer: Option C
:
C

The equivalent resistance is given by
$\frac{1}{R} = \frac{1}{60} + \frac{1}{30} = \frac{3}{60}$
R = 20 ohm. Therefore $I = \frac{2}{20} = \frac{1}{10} A$

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