1 − i 1 + i is equal to Options: A . &nbsp cos π 2 +isin π 2 B . &nbsp cos π 2 -isin π 2 C . &nbsp sin π 2 +icos π 2 D . &nbsp None of these

Answer: Option B : B 1 − i 1 + i = ( 1 − i ) ( 1 − i ) ( 1 + i ) ( 1 − i ) = 1 + ( i ) 2 − 2 i 1 + 1 =-i Which can be written as cos π 2 -isin π 2

1−i1+i is equal to

Question -

$\frac{1 - i}{1 + i}$ is equal to

Options:

A . cos

\frac{π}{2}

+isin

\frac{π}{2}

B . cos

\frac{π}{2}

-isin

\frac{π}{2}

C . sin

\frac{π}{2}

+icos

\frac{π}{2}

D . None of these

Answer: Option B
:
B

$\frac{1 - i}{1 + i}$ = $\frac{(1 - i) (1 - i)}{(1 + i) (1 - i)}$ = $\frac{1 + (i)^{2} - 2 i}{1 + 1}$ =-i

Which can be written as cos $\frac{π}{2}$ -isin $\frac{π}{2}$

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