Discussion Forum : Limits Continuity And Differentiability
Question -


The value of limx0xa[bx] is, ([.]G.I.F)

Options:
A .   0
B .  
C .   ba 
D .   does not exist
Answer: Option C
:
C
limx0xa[bx]
=limx0xa(bx{bx})
Since {bx}ϵ[0,1)
=limx0xa.{bx}=0
limx0xa[bx]=limx0(xa)(bx)
=limx0.ba
=ba

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