Discussion Forum : Limits Continuity And Differentiability
Question -


limxx+sinxxcosx=

Options:
A .   0
B .   1
C .   1
D .   does not exist
Answer: Option B
:
B
limxx+sinxxcosx
=limxx121+sinxxx121cosxx
We know, that for any value of x, sinx and cosx will be [-1,1]
So,  =limxSinxx=0 
And  =limxCosxx=0 
=x121+sinxx1+sinxx1+cosxx
=limx11
=1

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