Discussion Forum : Limits Continuity And Differentiability
Question -


limαβsin2αsin2βα2β2 is equal to 

Options:
A .   sin3β(4β) 
B .   sin2β(2β)
C .   sin8β(7β)
D .   sin6β(4β)
Answer: Option B
:
B
limαβsin2αsin2βα2β2=limαβsin(αβ)sin(α+β)(αβ)(α+β)=sin2β(2β)

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