Discussion Forum : Circles
Question -
The equation of the image of the circle x2+y2 - 6x - 4y + 12 = 0 by the line mirror x + y - 1 = 0
Answer: Option A
:
A
For the circle x2+y2 - 6x - 4y + 12 = 0.
This circle has centre C(3, 2) and radius (r) = 1
Image of (3, 2) w.r.t the line x + y - 1 = 0 = (-1, -2)
Equation of the circle with centre (-1, -2) and radius 1 is,
(x+1)2+(y+2)2 = 1
∴ Image of x2+y2 - 6x - 4y + 12 = 0 w.r.t x + y - 1 = 0 is,
x2+y2 + 2x + 4y + 4 = 0
Was this answer helpful ?
:
A
For the circle x2+y2 - 6x - 4y + 12 = 0.
This circle has centre C(3, 2) and radius (r) = 1
Image of (3, 2) w.r.t the line x + y - 1 = 0 = (-1, -2)
Equation of the circle with centre (-1, -2) and radius 1 is,
(x+1)2+(y+2)2 = 1
∴ Image of x2+y2 - 6x - 4y + 12 = 0 w.r.t x + y - 1 = 0 is,
x2+y2 + 2x + 4y + 4 = 0
Was this answer helpful ?
Login With Google
Old way of Login
Login With Email
Submit Your Solution hear: