To find the no. of common tangents, let's find the relation between distance between the centers of these circles and sum of their radii - 
Co-ordiantes of the center of first circle is (-1, - 4)
Co-ordiantes of the center of second circle is (2, 5)
thus the distance between them is -  $\sqrt{(3^2+9^2)}$
=  3$\sqrt{(}10)$
Now, the sum their radii will be - 
Radius of the first circle is -  2$\sqrt{(}10)$
Radius of the second circle is - $\sqrt{(}10)$
Sum of them will be -  3$\sqrt{(}10)$
Since, the distance between the centres is equal to sum of their radii
Number of common tangents will be 3.