Two vertices of an equilateral triangle are (–1, 0) and (1, 0) and its third vertex lies above the x-axis, the equation of the circumcircle is
Options:
A .  
3x2+3y2−2√3y=3
B .  
2x2+2y2−3√2y=3
C .  
x2+y2−2y=1
D .  
None
Answer: Option A : A Let A(–1, 0), B(1, 0) and C(0, b) be the vertices of the triangle, since C lies on the locus of points equidistance from A(–1, 0), and B(1, 0) i.e., y-axis. Then AB=AC ⇒√1+b2=2 ⇒b2=3 ⇒b=√3 [∵ b>0] Since the triangle is equilateral, the centre of the circumcircle is at the centroid of the triangle which is (0,1√3). Thus the equation of the circumcenter is, (x−0)2+(y−1√3)2=(1−0)2+(0−1√3)2 ⇒x2+y2−(2√3)y+13=1+13 ⇒3x2+3y2−2√3y=3
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