If the line x + 2by + 7 = 0 is diameter of the circle x 2 + y 2 − 6 x + 2 y = 0 , then b = Options: A . &nbsp 3 B . &nbsp -5 C . &nbsp -1 D . &nbsp 5

If the line x + 2by + 7 = 0 is diameter of the circle x2+y2−6x+2y=0, th

Question -

If the line x + 2by + 7 = 0 is diameter of the circle $x^{2} + y^{2} - 6 x + 2 y = 0$ , then b =

Options:

A . 3

B . -5

C . -1

D . 5

Answer: Option D
:
D
Here the centre of circle (3, -1) must lie on the line x + 2by + 7 = 0
Therefore, 3 - 2b + 7 = 0

\Rightarrow

b = 5

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