The power of (2,1) with respect to the circle 2x2+2y2−8x−6y+k = 0 is positive if
2x2+2y2−8x−6y+k = 0
⇒x2+y2−4x−3y+(k2) = 0
4+1−8−3+k2>0
k2−6>0→k>12
Your email address will not be published. Required fields are marked *
Submit Your Solution hear: