Probability of a fraudster being caught is 1 2 and committing a fraud is 3 5 . What is his chance of not going to jail? Options: A . &nbsp 70% B . &nbsp 50% C . &nbsp 40% D . &nbsp 35%

Probability of a fraudster being caught is 12 and committing a fraud is 35. Wh

Question -

Probability of a fraudster being caught is $\frac{1}{2}$ and committing a fraud is $\frac{3}{5}$ . What is his chance of not going to jail?

Options:

A . 70%

B . 50%

C . 40%

D . 35%

Answer: Option A
:
A

P(not going to jail)= P( F')+ P(F intersection C')

where P(F) is the probability of commiting a fraud and P(C) is the Probability of being caught

P(F')= $\frac{2}{5}$

P(C')= $\frac{1}{2}$

P(F intersection C')= P(F) × P(C')= $\frac{3}{5} \times \frac{1}{2} = \frac{3}{10}$

P(not going to jail)= $\frac{2}{5} + \frac{3}{10} = \frac{7}{10} = 70 %$

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