The minimum value of the function defined by f(x) = minimum {x, x+1,2

Question -

The minimum value of the function defined by f(x) = minimum {x, x+1,2 - x } is

Options:

A . 0

B .

\frac{1}{2}

C . 1

D .

\frac{3}{2}

Answer: Option D
:
D

$∵$ f(x) = maximum {x, x + 1, 2-x}

$∴$ Minimum value of function $= \frac{3}{2}$

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