The value of b such that the scalar product of the vector ^i+^j+^k with the unit vector parallel to the sum of the vectors 2^i+4^j+5^k and b^i+2^j+3^k is one, is
Options:
A .  
-2
B .  
-1
C .  
0
D .  
1
Answer: Option D : D The unit vector parallel to the sum of the vectors 2^i+4^j−5^k and b^i+2^j+3^k is ^n=(2+b)^i+6^j−2¨k√(2+b)2+62+(−2)2=(2+b)^i+6^j−2¨k√b2+4b+44 Now,(^i+^j+^k).^n=1 ⇒2+b+6−2=√b2+4b+44⇒b=1
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