Let ABCD be a parallelogram whose diagonals intersect at P and let O be the origin, then −−→OA+−−→OB+−−→OC+−−→OD equals
Options:
A .  
−−→OA
B .  
2−−→OP
C .  
3−−→OP
D .  
4−−→OP
Answer: Option D : D Since, the diagonals of a parallelogram bisect each other. Therefore, P is the middle point of AC and BD both. ∴−−→OA+−−→OC=2−−→OPand−−→OB+−−→OD=2−−→OP⇒−−→OA+−−→OB+−−→OC+−−→OD=4−−→OP
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