If a,b represent −−→AB,−−→BC respectively of a regular hexagon ABCDEF then −−→CD,−−→DE,−−→EF,−−→FA are
Options:
A .  
b-a, -a, -b, a-b
B .  
A-b, a, b, b-a
C .  
b-a, a, b, a-b
D .  
A-b,-a,-b, b-a
Answer: Option A : A ABCDEF is a regular hexagon ⇒⃗AD=2⃗BC,⃗ED=⃗AB,⃗FE=⃗BC,⃗FA=⃗DC Given ⃗AB=a,⃗BC=b Now ⃗AB+⃗BC+⃗CD=⃗AD⇒a+b+⃗CD=2⃗BC ⇒⃗CD=2b−(a+b)=b−a⃗DE=⃗BA=−⃗AB=−a,⃗EF=⃗CB=−⃗BC=−b⃗FA=⃗DC=−⃗CD=−(b−a)=a−b
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