The hybridisation of Fe in [FeF6]3− is sp3d2, the number of unpair

Question -

The hybridisation of Fe in $[F e F_{6}]^{3 -}$ is $s p^{3} d^{2}$ , the number of unpaired electrons present is

Options:

A . 2

B . 4

C . 5

D . 1

Answer: Option C
:
C
Here,

F e^{3 +}

had

d^{5}

configuration and it is an outer orbital complex.

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