H 2 S acts only as a reducing agent while S O 2 can act both as a reducing and oxidizing agent because Options: A . &nbsp S in H 2 S has - 2 oxidation state B . &nbsp S in S O 2 has oxidation state + 4 C . &nbsp Hydrogen in H 2 S more +ve than oxygen D . &nbsp Oxygen is more - ve in S O 2

H2S acts only as a reducing agent while SO2 can act both as a reducing an

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Question -

$H_{2} S$ acts only as a reducing agent while $S O_{2}$ can act both as a reducing and oxidizing agent because

Options:

A . S in

H_{2} S

has - 2 oxidation state

B . S in

S O_{2}

has oxidation state + 4

C . Hydrogen in

H_{2} S

more +ve than oxygen

D . Oxygen is more - ve in

S O_{2}

Answer: Option A
:
A and B

In $H_{2} S$ , Sulphur atom exhibits (-2) oxidation state, which is the least for the pnictogen.
As for its highest oxidation state - Sulphur exhibits (+6) in $H_{2} S O_{4}$ .
In $S O_{2}$ , sulphur exhibits a (+4) oxidation state, which is in between the extremes.
Hence $S O_{2}$ shows both oxidising and reducing properties.

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