When KMnO4 acts as an oxidising agent and ultimately forms [MnO4]−2, MnO2, Mn2O3, Mn+2 then the number of electrons transferred in each case respectively is
This has to be answered based on the oxidation number of the central metal atom in each case.
To start with Mn has +7 oxidation number in KMnO4. Likewise, we have
+6MnO2−4
+4MnO2
+3Mn2O3
+2Mn2+
The number of electrons transferred in each case is 1, 3, 4, 5 respectively.
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