In the reaction, 8Al + 3Fe3O4→4Al2O3 + 9Fe, the num

Question -

In the reaction, $8 A l + 3 F e_{3} O_{4} \to 4 A l_{2} O_{3} + 9 F e$ , the number of electrons transferred from reductant to oxidant is:

Options:

A . 8

B . 4

C . 7

D . 24

Answer: Option D
:
D
Elemental metallic Aluminium carries an oxidation number of 0.
From the products, we see that

0 A l

becomes

3 + A l^{3 +}

.
Clearly, Aluminium is the reducing agent.
There are 8 Aluminium atoms on the left and they all become

A l^{3 +}

.
So overall, there are 24 electrons transferred.

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