What is the correct IUPAC name of the compound? C H 2 = C H − C H 2 − C ≡ C H ? Options: A . &nbsp 1,4-Pentenyne B . &nbsp Pent-1-en-4-yne C . &nbsp Pent-1-yn-4-ene D . &nbsp 1, 4-Pentynene

What is the correct IUPAC name of the compound? CH2=CH−CH2−C&#x

Question -

What is the correct IUPAC name of the compound?

$C H_{2} = C H - C H_{2} - C \equiv C H$ ?

Options:

A . 1,4-Pentenyne

B . Pent-1-en-4-yne

C . Pent-1-yn-4-ene

D . 1, 4-Pentynene

Answer: Option B
:
B

While naming, the double bond gets a lower number than the triple bond.

$C 1 H_{2} = C 2 H - C 3 H_{2} - C 4 \equiv C 5 H$

Wort root = pent

Pent-1-en-4-yne

Not 4-Penten-1-yne

Because, if there is a choice in numbering, the double bond is always given preference over the triple bond.

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