The total number of pi-bonds in C H 2 = C H − C H = C H − C ≡ C H are ______. Options: A . &nbsp two B . &nbsp three C . &nbsp four D . &nbsp five

The total number of pi-bonds in CH2=CH−CH=CH−C≡CH a

Question -

The total number of pi-bonds in $C H_{2} = C H - C H = C H - C \equiv C H$ are ______.

Options:

A . two

B . three

C . four

D . five

Answer: Option C
:
C

\begin{matrix} Nature of bond & Number of sigma bonds & Number of pi-bonds Single bond & 1 & 0 Double bond & 1 & 1 Triple bond & 1 & 2 \end{matrix}

In the compound

C H_{2} = C H - C H = C H - C \equiv C H

, there are (2

\times

1) + (1

\times

2) = 4 pi-bonds in total.

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