Discussion Forum : Alcohols Phenols And Ethers
Question -


Propan-1-ol can be prepared from propene by alcohol

Options:
A .   H2O/H2SO4
B .   Hg(OAc)2/H2O followed by NaBH4
C .   B2H6 followed by H2O2
D .   CH3CO2H/H2SO4
Answer: Option C
:
C

When propene reacts with mercuric acetate followed by NaBH4, it gives secondary or tertiary alcohols, in accordance with Markownikoff’s rule.  But, with diborane followed by H2O2, it gives primary alcohols which is in accordance with Anti-Markownikoff’s rule. 6CH3CH=CH2+B2H6H2O2−−CH3CH2CH2OH



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