The work done in pulling up a block of wood weighing 2 kN for a length of 10m on a smooth plane inclined at an angle of 15 ∘ with the horizontal is Options: A . &nbsp 4.36 kJ B . &nbsp 5.17 kJ C . &nbsp 8.91 kJ D . &nbsp 9.82 kJ

Answer: Option B : B W = m g s i n θ × s = 2 × 10 3 × s i n 15 ∘ × 10 = 5.17 k J

The work done in pulling up a block of wood weighing 2 kN for a length of 10m on

Discussion Forum : Work Power And Energy

Question -

The work done in pulling up a block of wood weighing 2 kN for a length of 10m on a smooth plane inclined at an angle of $15^{\circ}$ with the horizontal is

Options:

A . 4.36 kJ

B . 5.17 kJ

C . 8.91 kJ

D . 9.82 kJ

Answer: Option B
:
B

$W = m g s i n θ \times s$

$= 2 \times 10^{3} \times s i n 15^{\circ} \times 10$

$= 5.17 k J$

Was this answer helpful ?

Next Question

Discussion Forum : Work Power And Energy

Submit Your Solution hear: