The value of 81 ( 1 l o g 5 3 ) + 27 l o g 9 36 + 3 4 l o g 7 9 is equal to Options: A . &nbsp 49 B . &nbsp 625 C . &nbsp 216 D . &nbsp 890

Answer: Option D : D 81 ( 1 l o g 5 3 ) + 27 l o g 9 36 + 3 4 l o g 7 9 = 3 l o g 3 5 4 + 3 l o g 3 36 3 2 + 3 l o g 3 7 4 2 = 5 4 + 36 3 2 + 7 2 = 890

The value of 81(1log5 3)+27log9 36+34log7 9 is equal to

Discussion Forum : Inequalities Modulus And Logarithms

Question -

The value of $81^{(\frac{1}{l o g_{5} 3})} + 27^{l o g_{9} 36} + 3^{\frac{4}{l o g_{7} 9}}$ is equal to

Options:

A . 49

B . 625

C . 216

D . 890

Answer: Option D
:
D

81^{(\frac{1}{l o g_{5} 3})} + 27^{l o g_{9} 36} + 3^{\frac{4}{l o g_{7} 9}}

= 3^{l o g_{3} 5^{4}} + 3^{l o g_{3} 36^{\frac{3}{2}}} + 3^{l o g_{3} 7^{\frac{4}{2}}}

= 5^{4} + 36^{\frac{3}{2}} + 7^{2} = 890

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Discussion Forum : Inequalities Modulus And Logarithms

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