l o g 7 l o g 7 √ 7 ( √ 7 √ 7 ) = Options: A . &nbsp 3 l o g 2 7 B . &nbsp 1 − 3 l o g 3 7 C . &nbsp 1 − 3 l o g 7 2 D . &nbsp N o n e o f t h e s e

Answer: Option C : C l o g 7 l o g 7 √ 7 √ 7 √ 7 = l o g 7 l o g 7 7 7 8 = l o g 7 ( 7 8 ) = l o g 7 7 − l o g 7 8 = 1 − l o g 7 2 3 = 1 − 3 l o g 7 2

log7 log7 √7(√7√7)=

Discussion Forum : Inequalities Modulus And Logarithms

Question -

$l o g_{7} l o g_{7} \sqrt{7 (\sqrt{7 \sqrt{7}})} =$

Options:

A .

3 l o g_{2} 7

B .

1 - 3 l o g_{3} 7

C .

1 - 3 l o g_{7} 2

D .

N o n e o f t h e s e

Answer: Option C
:
C

l o g_{7} l o g_{7} \sqrt{7 \sqrt{7 \sqrt{7}}} = l o g_{7} l o g_{7} 7^{\frac{7}{8}} = l o g_{7} (\frac{7}{8})

= l o g_{7} 7 - l o g_{7} 8 = 1 - l o g_{7} 2^{3} = 1 - 3 l o g_{7} 2

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Discussion Forum : Inequalities Modulus And Logarithms

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