Discussion Forum : Trigonometric Functions
Question -


The value of sin25+sin210+sin215+..............


+sin285+sin290 is equal to

Options:
A .   7
B .   8
C .   9
D .   192
Answer: Option D
:
D

Given expression is


sin25+sin210+sin215+..............+sin285+sin290.


We know that sin90=1 or sin290=1


Similarly, sin45= 12 or sin245=12 and the angles are in A.P. of 18 terms. We also know that


sin285=[sin(905)]2=cos25.


Therefore from the complementary rule, we find sin25+sin285=sin25+cos25=1


Therefore,


sin25+sin210+sin215+.............+sin285+sin290


=(1+1+1+1+1+1+1+1)+1+12=912.



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