Discussion Forum : Binomial Theorem
Question -


In the expansion of (1+x1x)2, the coefficient of xn

Options:
A .   4n
B .   4n-3
C .   4n+1
D .   None of these
Answer: Option A
:
A

Given term can be written as (1+x)2(1x)2


=(1+2x+x2)[1+2x+3x2+.......+(n1)xn2+nxn1+(n+1)xn+...........]


= xn(n+1+2n+n1)+..........


Therefore coefficient of xn is 4n.



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