The equation of the circle whose centre is (1, -3) and which touches the line 2x - y - 4 = 0 is
Options:
A .  
5x2+5y2−10x+30y+49=0
B .  
5x2+5y2+10x−30y+49=0
C .  
5x2+5y2−10x+30y−49=0
D .  
None of these
Answer: Option A : A Radius of circle the required circle =∣∣∣2+3–4√5∣∣∣=1√5 Therefore the equation is, (x−1)2+(y+3)2=15 i.e, x2+y2−2x+6y+1+9=15 i.e, 5x2+5y2−10x+30y+49=0.
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