Discussion Forum : Trigonometric Functions
Question -


cos248sin212=
 

Options:
A .   514
B .   5+18
C .   314
D .   3+122
Answer: Option B
:
B

cos2Asin2B = cos(A + B). Cos(A - B)


cos248sin212=cos60.cos 36


=12(5+14)=5+18



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